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stepan [7]
3 years ago
11

A quadratic function has a line of symmetry at x = –3 and a zero at 4.

Mathematics
2 answers:
vesna_86 [32]3 years ago
7 0
I have my hints here on how to solve the questions one and two:

<span>Q1: Just find the distance from -3 to 4. That's 7.

Q2: It is 7 units to the left of -3. Subtract 7 from -3. That's -10
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Mazyrski [523]3 years ago
3 0

Answer:

Part 1) 7\ units

Part 2) The other zero is -10

Step-by-step explanation:

we know that

If the line of symmetry is equal to x=-3

then

the quadratic function is a vertical parabola and the x-coordinate of the vertex is -3

Part 1) What is the distance from the given zero to the line of symmetry?

The distance is equal to the absolute value of the difference of -3 from 4

d=\left|4-\left(-3\right)\right|=7\ units  

Part 2) What is the other zero of the quadratic function?

we know that

In a quadratic function the distance from the zero's to the line of symmetry is equal

so

Subtract 7 from -3

-3-7=-10

The other zero is -10




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