Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
I really don’t know sorry I would help you but I can genesis hdbdbhs hebdbh
Answer:
4.4N, 263.4°
Step-by-step explanation:
The sum of all forces must add to zero:
The forces in the x-plane:
∑F = 3N + (cos 120°)*5N + x = 0
x = -(3N + (cos 120°)*5N)
x = -0.5N
The forces in the y-plane:
∑F = (sin 120°)*5N + y = 0
y = -(sin 120°)*5N = -√(3/4)*5N = -4.3N
The magnitude of the unknown force U is:
U = √(x² + y²) = √19 = 4.4N
The direction is given by:
tanФ = y/x
Ф = 263.4°
Answer:
yes
Step-by-step explanation:
If 2 lines are perpendicular then the product of their slopes = - 1
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - x - 4 ← is in slope- intercept form
with slope m = - 1
5x - 5y = 20 ( subtract 5x from both sides )
- 5y = - 5x + 20 ( divide all terms by - 5 )
y = x - 4 ← in slope- intercept form
with slope m = 1
Thus product of their slopes is - 1 × 1 = - 1
Therefore the lines are perpendicular
22 need more
150-56=94
20*3 = 60
94-60 = 34
34-12= 22
