Ask question

Ask question

All categories

3 years ago

15

On Monday, Ken spent half of his money on a new game. The next day he earned $12 mowing lawns. He now has $32. How much money di

d Ken have before he bought the game?

1 answer:

Free_Kalibri [48]3 years ago

7 0

Answer:

He had $20 before he bought the game, you can use subtraction to find out how much Ken had

$32 - $12 = $20

You might be interested in

Find the two square roots of the number 169

Mazyrski [523]

One root belonged to an old tree next to the road, and the other is part of a small tree.

4 0

3 years ago

For f(x) = 4x2 + 13x + 10, find all values of a for which f(a) = 7.

sammy [17]

Answer:

0.84

Step-by-step explanation:

4x2+13a+10=7

13a=7-10-8

13a=-11

a=-11:13

a=0.84

4 0

3 years ago

Find the volume of a cylinder with a diameter of 8 inches and a height that is three times the radius round to the nearest hundr

patriot [66]

volume for cylinder = pi x r^2 x h

radius = half the diameter = 8/2 =4

height = 3 times the radius = 3*4 =12

using 3.14 for pi

volume = 3.14 x 4^2 x 12 = 602.88 cubic inches

5 0

3 years ago

AYUDAAA PORFAVOOOOOOR!!

galben [10]

Answer:

4

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago