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Lelu [443]
4 years ago
5

Suppose that we have two events, A and B, with P(A) = 0.40, P(B) = 0.60, and P(A ∩ B) = 0.20. (a) Find P(A | B). (Round your ans

wer to four decimal places.) P(A | B) = (b) Find P(B | A). P(B | A) = (c) Are A and B independent? Why or why not? A and B independent because .
Mathematics
1 answer:
Svetach [21]4 years ago
7 0

Answer:

a.) 0.3333

b.) 0.5

c.) A and B are NOT independent

Step-by-step explanation:

We're given P(A) = 0.4, P(B) = 0.6, P(AnB)

a.) From law of probability,

P(A l B) = P(AnB)/P(B)

P (A l B) = 0.2/0.6 = 0.3333

b.) similarly, going by the above law of probability,

P(B l A) = P(BnA)/P(A)

P(B l A) = 0.2/0.4 = 0.5

c.) Two events A and B are said to be independent if mathematically, any of the following conditions are satisfied.

i.) P(A l B) = P(A)

ii.) P(B l A) = P(B)

Since both conditions stated above are not satisfied, that is:

P(A l B) [0.3333] ≠ P(A) [0.4]

P(B l A) [0.5] ≠ P(B) [0.6]

then the two events A and B are NOT Independent

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Read 2 more answers
Alex and Bryan are giving an exam. The probability Alex gets an A is 0.9, the probability Bryan gets an A is 0.8 and the probabi
VARVARA [1.3K]

Answer:

The probability that either Alex or Bryan get an A is 0.9

Step-by-step explanation:

Before we proceed to answer, we shall be making some important notation;

Let A = event of Alex getting an A

Let B = event of Bryan getting an A

From the question, P(A) = 0.9, P(B) = 0.8 and P(A ∩ B^{c} ) = 0.1

We are to calculate the probability that either Alex or Bryan get an A which can be represented as P(A ∪ B)

We can use the addition theorem here;

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)  .......................(i)

Also,

P(A) = P(A ∩ B^{c} )  +   P(A ∩ B)   .........................(ii)

We can insert ii into i and we have;

P(A ∪ B) =  P(A ∩ B^{c} )  +   P(A ∩ B)  + P(B) - P(A ∩ B) =   P(A ∩ B^{c} ) + P(B) = 0.1 + 0.8 = 0.9

5 0
3 years ago
Anybody know the answer?
klio [65]
The equation of the unit circle is
                                               x^2 + y^2 = 1
If x = 5/8, then solving for y
                                         (5/8)^2 + y^2 = 1
                                                          y^2 = 1 - 25/64
                                                          y^2 = 39/64
                                                          y     = sqrt(39/64)
We use the positive square root because positive x-coordinate and positive y-coordinate is in the first quadrant.
Therefore the answer to this question is sqrt(39)/8
5 0
3 years ago
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