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Lelu [443]
3 years ago
5

Suppose that we have two events, A and B, with P(A) = 0.40, P(B) = 0.60, and P(A ∩ B) = 0.20. (a) Find P(A | B). (Round your ans

wer to four decimal places.) P(A | B) = (b) Find P(B | A). P(B | A) = (c) Are A and B independent? Why or why not? A and B independent because .
Mathematics
1 answer:
Svetach [21]3 years ago
7 0

Answer:

a.) 0.3333

b.) 0.5

c.) A and B are NOT independent

Step-by-step explanation:

We're given P(A) = 0.4, P(B) = 0.6, P(AnB)

a.) From law of probability,

P(A l B) = P(AnB)/P(B)

P (A l B) = 0.2/0.6 = 0.3333

b.) similarly, going by the above law of probability,

P(B l A) = P(BnA)/P(A)

P(B l A) = 0.2/0.4 = 0.5

c.) Two events A and B are said to be independent if mathematically, any of the following conditions are satisfied.

i.) P(A l B) = P(A)

ii.) P(B l A) = P(B)

Since both conditions stated above are not satisfied, that is:

P(A l B) [0.3333] ≠ P(A) [0.4]

P(B l A) [0.5] ≠ P(B) [0.6]

then the two events A and B are NOT Independent

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10,935 bunnies at the end of 7 weeks  

Step-by-step explanation:

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I may be <u><em>way </em></u>off, forgive me, but I hope this helps anyway, have a good day!!

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3 years ago
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Step-by-step explanation:

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Resuelve los problemas de una bodega que exporta tomates al extranjero
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4.\frac{15}{10} o 1\frac{5}{10}

5.\frac{16}{6} o 2\frac{4}{6}

6.\frac{8}{4} o 2

1.1 Solucioné el problema convirtiendo el .25 en fracción.

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\frac{1}{4}

\frac{1}{3}

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Step-by-step explanation:

Acuerdate que para solucionar las fracciones mixtas solo tienes que dividir el denominador al nominador, por ejemplo en si tienes \frac{10}{3} entonces el 3 cabe 3 veces en el 10, y sobra 1, entonces quedamos que en mixta la fracción sería 3\frac{1}{3}

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Cómo el 10 cabe 1 vez en el 15, tenemos un entero y sobran 5:

1\frac{5}{10}

5 0
3 years ago
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