Hey there!
To solve this, we can use division. First, lets turn
into an improper fraction:

So, we have

We can multiply by the reciprocal:

That gives us

Hope it helps and have a great day!
Step-by-step explanation:
<em><u>a</u></em><em><u>)</u></em><em><u> </u></em><em><u>3</u></em><em><u>6</u></em><em><u> </u></em><em><u>on </u></em><em><u>section</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>qus</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>titik </u></em>
The third option is the right one
Answer: 0.625
Step-by-step explanation:
Given : The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed with interval= [0 minutes, 6 minutes]
The probability density function :-

The interval of required event = [2.25 seconds, 6 seconds]
Now, the probability that a randomly selected passenger has a waiting time greater than 2.25 minutes is given by :-

Hence, the probability that a randomly selected passenger has a waiting time greater than 2.25 minutes = 0.625