There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
Ans: (c)
y = k/x^2
when y = 100, x = 1
100 = k/1^2
k = 100
when x = 2,
y = 100/2
= 50
(u/rachelmarrons already gave you the answer but here’s a step-by-step explanation in case you needed it haha)
Do what is in the parentheses then add
