5cos (2x)+7=cos (2x)+8, 4cos (2x)=1, cos (2x)=1/4, 2x=arccos(1/4), x=(1/2)arccos (1/4). I used x instead of theta, and arccos is cos inverse
If the -1 is not included, then your answer is 3.17.
2(3x-4)=11
3x2=6 and -4x2= -8
6x-8=11
+8 +8
6x=19
/6 /6
X= 3.17
Answer:
D={3,9}
The numbers are 3 and 9
Step-by-step explanation:
The set A
={,,,,,,,,,}
Let B be the sub set of A containing odd numbers
B={1,3,5,7,9}
Let C be the sub set of A containing multiply of 3
C= {3,6,9}
Now let D be the be the sub set of A containing both odd numbers and multiples of 3
D={3,9}
The answer is D. -24 - 49i/13
