2 years ago

The Gainey’s are going to start their savings by saving $10 on the first day and then 10 each day of the month

Mathematics

1 answer:

Tasya [4]2 years ago

7 0

is there more to this? if so i would love to help.

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Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a

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Answer:

The area that was not painted is $(2x^{2}-6x+6)\ units^{2}$

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

$A=LW$

In this problem we have

$L=2x-3$

$W=x$

substitute

$A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}$

step 2

Find the area that was painted

$A=(3)(x-2)\\A=(3x-6)\ units^{2}$

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

$A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}$

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Step-by-step explanation:

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