All categories

3 years ago

Solve it...........!!!!

Mathematics

2 answers:

timofeeve [1]3 years ago

4 0

Answer:

I think it is correct and is 1 and 2

Bond [772]3 years ago

3 0

Step-by-step explanation:

5×4^(x+1)-16^x=64

0=64+16^x-5×4¹×4^x

0=(4^x)²-2×4^x×10+10²-10²+64

0=(4^x-10)²-36

(4^x-10)²=36

4^x-10=√36

4^x=+-6+10

when positive

4^x=4²

:.x=2

when negative

4^x=4

:.x=1

:.x=1,2 answer.

You might be interested in

(a) One ball is selected at random from the bag.

lana [24]

Answer:

a) The probability is 1/5

bi) The probability each ball is even will be 2/5

bii) The probability the sum of the numbers on the ball is not more than 10 is 16/25

(that's what I think it is)

3 0

3 years ago

PLEASE HELP ;)<br> Who did it right?<br><br> Find the slope of the line perpendicular to 2x+3y=8

levacccp [35]

Answer:

Marissa.

Step-by-step explanation:

To find perpendicular slope you basically take the slope of the given line and reverse whatever sign it had previously. (If it was negative, it would become positive. If it was positive it would become negative.)

By doing -A/B it make the previous slope negative.

Brandon only flipped the fraction which would just result in the slope being slightly steeper, or in this case, less steep than the previous line, rather than making it perpendicular.

Hope this helps! Stay safe and if you have any questions feel free to ask!

6 0

3 years ago

what is the y-intercept of the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15

ohaa [14]

The slope of the given line is the coefficient of x, 3/5. The slope of the perpendicular line will be the negative reciprocal of that: -1/(3/5) = -5/3.

The point-slope form of the equation for a line of slope m through point (h, k) can be written ...

... y = m(x -h) +k

For your point and the slope found above, this becomes

... y = (-5/3)(x -15) -5

When x=0, this is

... y = (-5/3)(-15) -5 = 20

The y-intercept is 20.

3 0

3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$