The matrix whose columns are the coordinate vectors of the Hermite polynomials relative to the
standard basis {1,t,t²,t³} of P3 is given by:
Since this matrix is already in row echelon form and there are 4 nonzero pivots, then its columns are linearly
independent. Since the coordinate vectors form a linearly independent set, then the Hermite polynomials
form a linearly independent set in P3: The dimension of P3 is 4; so this set of Hermite polynomials forms a basis for P3:
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Answer:
rad66/11
Step-by-step explanation:
Using Sohcahtoa, you can find that the tangent is the opposite side over the adjacent side. This means that the tangent of angle X is 2rad6/2rad11. You then simplify it to rad6/rad11. Preferably, a radical shouldn't be in the denominator. You can muliply both sides by rad 11 to balance the equation into rad66/11.