Help me please!!!!!!!!!!! i

Mathematics

1 answer:

Neporo4naja [7]3 years ago

6 0

Answer:

rad66/11

Step-by-step explanation:

Using Sohcahtoa, you can find that the tangent is the opposite side over the adjacent side. This means that the tangent of angle X is 2rad6/2rad11. You then simplify it to rad6/rad11. Preferably, a radical shouldn't be in the denominator. You can muliply both sides by rad 11 to balance the equation into rad66/11.

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You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$