Find total surface area (18*12)*2+ (18*8)*2+ (12*8)*2= 192 +288 432+288+192= 912
then subtract surface area of doors
(3*7)2=42 then subtract windows 3*5(3)=45 then subtract the floor 18*12=216
912-42-45-216= 609 sq ft he should only need 2 and a small portion of a third to paint your room i believe what his math must have been was 18*12*8=1728 then subtract -42-45-216 for the floor windows and doors to get 1425 and even then he underestimates with his inaccurate figures
so first 609 sq ft he should only need 2 and a small portion of a third to paint your room and 2 get a new painter bcus this guy cant math hope i helped if so give brainliest answer-J (:
Answer:
I(x)=x+1
Step-by-step explanation:
550 sq m
Step-by-step explanation:
Step 1 :
The length of the first cross road the park is 70 m
The width of the first cross road the park is 5 m
So its area is 70 * 5 = 350 sq m
Step 2 :
The length of the second cross road the park is 45 m
The width of the width cross road the park is 5 m
So its area is 45 * 5 = 225 sq m
Step 3 :
The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m
This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park
So we have
the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m
Answer:
Because Rhomboids have adjacent sides that makes it equal, and also both sides have the same meeting point which is M.
Step-by-step explanation:
