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2 years ago

The first step in solving 7/8 =3 x - 5/11 is to subtract 5/11 from both sides of the equation. True False

1 answer:

5 0

The first step in solving 7/8 =3 x - 5/11 is to subtract 5/11 from both sides of the equation. True False? Answer is false

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PLEASEEE HELP MEEE

Pavlova-9 [17]

Answer:40

Step-by-step explanation:

8 0

2 years ago

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I need help i dont understand

solmaris [256]

Answer:

D. 1/3^3

Step-by-step explanation:

Divide 3/3 as usual and get 1.

When dividing exponents, you are actually subtracting them. 5-8 = -3.

D is the answer because positive exponents in the denominator of the fraction is the same as a negative exponent in the numerator.

5 0

2 years ago

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Among all right triangles whose hypotenuse has a length of 12 cm, what is the largest possible perimeter?

Veronika [31]

Answer:

Largest perimeter of the triangle =

$P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)$

Step-by-step explanation:

We are given the following information in the question:

Right triangles whose hypotenuse has a length of 12 cm.

Let x and y be the other two sides of the triangle.

Then, by Pythagoras theorem:

$x^2 + y^2 = (12)^2 = 144\\y^2 = 144-x^2\\y = \sqrt{144-x^2}$

Perimeter of Triangle = Side 1 + Side 2 + Hypotenuse.

$P(x) = x + \sqrt{144-x^2} + 12$

where P(x) is a function of the perimeter of the triangle.

First, we differentiate P(x) with respect to x, to get,

$\frac{d(P(x))}{dx} = \frac{d(x + \sqrt{144-x^2} + 12)}{dx} = 1-\displaystyle\frac{x}{\sqrt{144-x^2}}$

Equating the first derivative to zero, we get,

$\frac{dP(x))}{dx} = 0\\\\1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0$

Solving, we get,

$1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0\\\\x = \sqrt{144-x^2}}\\\\x^2 = 144-x^2\\\\x = \sqrt{72} = 6\sqrt{2}$

Again differentiation P(x), with respect to x, using the quotient rule of differentiation.

$\frac{d^2(P(x))}{dx^2} = \displaystyle\frac{-(144-x^2)^{\frac{3}{2}}-x^2}{(144-x)^{\frac{3}{2}}}$

At x = $6\sqrt{2}$ ,

$\frac{d^2(V(x))}{dx^2} < 0$

Then, by double derivative test, the maxima occurs at x = $6\sqrt{2}$

Thus, maxima occurs at x = $6\sqrt{2}$ for P(x).

Thus, largest perimeter of the triangle =

$P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)$

7 0

2 years ago

1 litre is approximately 1.75 pints, 1 gallon = 8 pints, calculate the approcimate number of gallons that are equal to 48000cm3

Umnica [9.8K]

Answer:

$10.5\ gal$

Step-by-step explanation:

we know that

$1,000\ cm^{3} =1\ l$

$1\ l=1.75\ pints$

$1\ gal=8\ pints$

we have

$48,000\ cm^{3}$

step 1

Convert to liters

$48,000\ cm^{3}=48,000/1,000=48\ l$

step 2

Convert to pints

$48\ l=48*1.75=84\ pints$

step 3

Convert to gallons

$84\ pints=84/8=10.5\ gal$

7 0

2 years ago

Suppose that the x-values of the x-intercepts of the graph of y = f(x) are -6 and 5.

balu736 [363]

Answer: PAY ATTENTION IN CLASS AND STOP TALKING TO YOUR FRIENDS

Step-by-step explanation:

3 0

2 years ago