3 years ago

a machine worked for 5 hours and it used 4 kilowatts of eletricity . The machine used ___ of kilowatts each hour it worked,

Mathematics

1 answer:

Ivenika [448]3 years ago

8 0

The answer is 0.8 kilowatts because 4 divided by 5 is 0.8

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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

3 years ago

A person runs 1 4/5 miles in 1/5 of an hour determine how many miles they are running per hour

asambeis [7]

Multiply 1 4/5 by 5
9/5 * 5/1 = 45/5 = 9 miles

8 0

2 years ago

Read 2 more answers

Joseph buys 10 cookies. He eats 7 of them. He wants to know how many cookies he has left.

AysviL [449]

Answer:

subtract 10-7 which is 3 cookies