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3 years ago

Simplify: this problem please im confused

Mathematics

2 answers:

nignag [31]3 years ago

7 0

Answer:

2.4

Step-by-step explanation:

-3.6+2=-1.6, -1.6*-1.5=2.4

Ksju [112]3 years ago

5 0

Answer:

Step-by-step explanation:

Add -3.6 +2 =-1.6

Multiply-1.6×-1.5 to get your answer

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Solve the equation a/a^2-9 +3/a-3=1/a+3

MAXImum [283]

Answer is: a= -4
STEP
1
:

1
Simplify —————
a + 3
Equation at the end of step
1
:

a 3 1
(————————+—————)-——— = 0
((a2)-9) (a-3) a+3
STEP
2
:

3
Simplify —————
a - 3
Equation at the end of step
2
:

a 3 1
(————————+———)-——— = 0
((a2)-9) a-3 a+3
STEP
3
:

a
Simplify ——————
a2 - 9
Equation at the end of step
3
:

a 3 1
(————————————————— + —————) - ————— = 0
(a + 3) • (a - 3) a - 3 a + 3

Equation at the end of step
4
:

(4a + 9) 1
————————————————— - ————— = 0
(a + 3) • (a - 3) a + 3
Pull out like factors :

3a + 12 = 3 • (a + 4)

Equation at the end of step
6
:

3 • (a + 4)
————————————————— = 0
(a + 3) • (a - 3)

3•(a+4)
——————————— • (a+3)•(a-3) = 0 • (a+3)•(a-3)
(a+3)•(a-3)

a+4 = 0

Subtract 4 from both sides of the equation :
a = -4

7 0

3 years ago

The value of `sqrt20` is between ______ and ______.

Anna71 [15]

Answer:

4.472135955

Step-by-step explanation:

7 0

3 years ago

Will mark brainliest for whoever answers

xeze [42]

Answer:

the third one

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Castel left the science museum and traveled toward the mountains. Sumalee left one hour later traveling 10 km/h faster in an eff

nadezda [96]

Castel's average speed from the science museum to mountains is 20 km/h

<h3>Average speed</h3>

Let x represent Castel' average speed.

Sumalee left one hour later and caught up with Castel after two hours, Let us assume the distance covered is d:

For Castel:

x = d / 3
d = 3x

For Sumalee:

x + 10 = d / 2
d = 2x + 20

3x = 2x + 20

x = 20 km/h

Therefore Castel's average speed from the science museum to mountains is 20 km/h

Find out more on average speed at: brainly.com/question/4931057

3 0

2 years ago

PLEASE HELP I NEED THIS NOW SO BADLY :(( Simplify: 2 1/4 x+(4 1/3 x−7 4/5 )÷2 3/5

prohojiy [21]

Answer:

$2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}$

Step-by-step explanation:

Considering the expression

$2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}$

Simplifying the expression

$\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}$

$\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{1}{4}=\frac{9}{4}$

$\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}$

$\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{3}{5}=\frac{13}{5}$

$\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}$

$\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 4\frac{1}{3}=\frac{13}{3}$

$\frac{9}{4}x+\left(\frac{13}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}$

$\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 7\frac{4}{5}=\frac{39}{5}$

$\frac{9}{4}x+\left(\frac{13}{3}x-\frac{39}{5}\right)\div \frac{13}{5}$

$\frac{9}{4}x=\frac{9x}{4}$

and

$\frac{\frac{13}{3}x-\frac{39}{5}}{\frac{13}{5}}=\frac{5\cdot \frac{65x-117}{15}}{13}$

So,

$\frac{9x}{4}+\frac{5\cdot \frac{65x-117}{15}}{13}$

$\mathrm{Least\:Common\:Multiplier\:of\:}4,\:13:\quad 52$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\frac{117x}{52}+\frac{\frac{4\left(65x-117\right)}{3}}{52}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$\mathrm{Join}\:117x+\frac{4\left(65x-117\right)}{3}:\quad \frac{611x-468}{3}$

$\frac{\frac{611x-468}{3}}{52}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$\frac{611x-468}{3\cdot \:52}$

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:52=156$

$\frac{611x-468}{156}$

$\mathrm{Factor}\:611x-468:\quad 13\left(47x-36\right)$

$\frac{13\left(47x-36\right)}{156}$

$\mathrm{Cancel\:the\:common\:factor:}\:13$

$\frac{47x-36}{12}$

Therefore, $2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}$

Keywords: algebraic expression , simplification

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7 0

4 years ago