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Paladinen [302]
2 years ago
9

When pasting text and tables,which of these paste options is generally available

Computers and Technology
1 answer:
Taya2010 [7]2 years ago
4 0

Answer:

For text and table in common: Keep Text Only

And hence, B. Paste as a text item is the correct option.

The above is the common option available in case we are pasting the Text or you are pasting the Table. If you copy a text and try to paste it, and when you will try to paste the table, then you will find this option in common, and hence it is the option that is generally available. Hence, B is the correct option.

Explanation:

Please check the answer section.

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Answer:kk ima do it

Explanation:

7 0
3 years ago
Read 2 more answers
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Please help me very important
3241004551 [841]

Answer:

C, Or D.

Explanation:

<em>Because A speed enhancing hard drive Can store any type of quick file if you just click on it will load fast. Same thing goes for a hard drive but you have to transfer the file</em>

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2 years ago
Which one of the following pieces of information would be allowed as part of a limited data set?
Inessa05 [86]
Phone number would be allowed
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3 years ago
The file includes 4993 tweets including the keyword 'election'. Each tweet is represented in a separate line. Write a program to
Likurg_2 [28]

Answer:

import re

with open("../../Downloads/Tweets.txt","r", encoding="utf-8") as tweets:

   myfile = tweets.readlines()

   for item in myfile:

       item = item.rstrip()

       mylist = re.findall("^RT (.*) ", item)

       if len(mylist) !=0:

           for line in mylist:

               if line.count("#") >=1:

                   ln = line.split("#")

                   dm = ln[1]

                   print(f"#{dm}")

Explanation:

The python source code filters the document file "Tweets" to return all tweets with a hashtag flag, discarding the rest.

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