Answer:
Following are the program in python language the name of the program is factors.py
num= int(input("Please enter a positive integer: "))#Read the number by user
print("The factors of ",num,"are:")
for k in range(2,num): #iterating over the loop
if(num%k==0): #checking the condition
print(k)#display the factor
Output:
Please enter a positive integer: 12
The factors of 12 are:
2
3
4
6
Explanation:
Following are the description of the program
- Read the number by user in the "num" variable
- Iterating the for loop from k=2 to less then "num".
- In the for loop checking the factor of "num" variable by using % operator.
- Finally display the factor by using print function
Over the years, operating systems have sought to be more efficient, which is why it is vital that the use of main memory such as ram be as intelligent as possible, so that operating systems are more efficient.
Segmentation is a process of dividing the program into logical units, such as sub functions, arrays, variables, etc., making it possible to have processes divided into pieces so that it is easy to access each of the processes that this leads to its execution. Segmentation allows the programmer to contemplate the memory as if it had several address spaces or segments. References to memory consist of an address of the form segment number - offset.
Pagination is a technique where memory space is divided into physical sections of equal size, called page frames. The programs are divided into logical units, called pages, that are the same size as the page frames. In this way, an information page can be loaded in any page frame. The pages serve as an information storage unit and transfer between main memory and auxiliary or secondary memory. Each frame is identified by the frame address, which is in the physical position of the first word in the page frame.
Answer:
Replace /* Your code goes here */ with
for(i =0; i<NUM_VALS; i++)
{
printf("%d", origList[i]*offsetAmount[i]);
printf(";");
}
Explanation:
The first line is an iteration statement iterates from 0 till the last element in origList and offsetAmount
for(i =0; i<NUM_VALS; i++)
{
This line calculates and print the product of element in origList and its corresponding element in offsetAmount
printf("%d", origList[i]*offsetAmount[i]);
This line prints a semicolon after the product has been calculated and printed
printf(";");
Iteration ends here
}
<u>Answer</u>:
<em>It is possible to sort data in word. For doing this, you must have content in the form of list.
</em>
<u>Explanation:</u>
<em>1. Select the text in numbered list / bulleted list
</em>
<em>2. Click on the Home tab, Paragraph group, Click on Sort. You well get a Sort Text dialog box</em>
<em>3. In the dialog box , Click Paragraph, Text, Ascending / descending. So you can change the way it sorted by using the same dialog box whenever required.
</em>
<em>
In addition to sorting text, you can sort date and also sort number.
</em>
