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faust18 [17]
3 years ago
8

A circle has an area of 50 square meters what is the diameter

Mathematics
2 answers:
topjm [15]3 years ago
7 0
Area = πr²
50 = πr²
r = √50/π

so diameter = 2√50/π
which is = 7.98m to 3sf
Serjik [45]3 years ago
5 0
<span>d+7.98 meters 

This the answer

</span>
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In order to apply the law of sines to find the length of the side of a triangle, it is enough to know which of the following?
larisa86 [58]

Answer:

We must have two angles and a side.

A is the correct option.

Step-by-step explanation:

For any triangle ABC,  the law of sine is given by

\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}

From this formula it is clear that in order to find the length of the side of the triangle, we must have two angles and a side.

Let us understand this by assuming that we need to find a (length of the side). From the formula, we have

\frac{a}{\sin A}=\frac{b}{\sin B}\\\\a=\frac{b\sin A}{\sin B}

Thus, to find the length a, we must have b, sin A and sin B.

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Which is the equation of the line with slope 3 that contains point (-1, 5)?
sattari [20]

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I will mark you brainiest if you can answer this
Klio2033 [76]

Answer:

B

Step-by-step explanation:

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2 years ago
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aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

{3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\

3y^{2}.\frac{d^{2} y}{dx^{2}} =  - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} =  - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} =  - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} =  - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} =  - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} =  - \frac{-2x}{y^{5}}

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2 years ago
When a number is decreased by 45%, the result is 9. What is the original number to the nearest tenth?
Paul [167]

Answer:

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Step-by-step explanation:

To decrease a number by 45% of its value, you subtract the 45%. To get 45%, you multiply the number by 0.45.

So, if x is the original number, then the equation for this word problem would be x - 0.45x = 9.

To solve, we first subtract 0.45x from x, which is 0.55x. This means that 0.55x is equal to 9. To simplify, we can divide both sides by 0.55. 9/0.55 is 16.36363636..., etc. The nearest tenth would be 0.4, so your answer is 16.4

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