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Oksana_A [137]
3 years ago
8

Reminder when performing your check step, always substitute your solution by enclosing it in parentheses. -x + 3 = 2(3 - 2x)

Mathematics
1 answer:
Wittaler [7]3 years ago
8 0

Answer:

x = 1

Step-by-step explanation:

For the equation given, we have to solve for the value of "x".

First, when simplifying, we will need the distributive property shown below:

<u>Distributive Property:</u>

a(b - c) = ab - ac

Now, lets do algebra:

-x + 3 = 2(3 - 2x)\\-x+3=2(3)-2(2x)\\-x+3=6-4x\\-x+4x=6-3\\3x=3\\x=\frac{3}{3}\\x=1

The value of x is 1

Lets substitute x = 1 into equation to check:

-x + 3 = 2(3-2x)

LEFT SIDE:

-(1) + 3

= -1 + 3

=2

RIGHT SIDE:

2(3-2x)

2(3-2(1))

=2(3-2)

=2(1)

= 2

<em>This is indeed the solution since left hand side equals right hand side</em>

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Answer: after 3 seconds

when  the ball hit the ground => - 5t² + 14t + 3 = 0

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⇔ t = 3 or t = -1/5

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Step-by-step explanation:

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In how many ways can 5 different novels, 4 different mathematics books, and 1 biology book be arranged on a bookshelf if
zalisa [80]

Question Continuation:

if   (a) the books can be arranged in any order?  

(b) the mathematics books must be together and the novels must be together?

Answer:

(a) 3628800  ways

(b) 17280 ways

Step-by-step explanation:

Given

Novels = 5

Mathematics = 4

Biology = 1

Solving (a): In any order

This implies that there is no restriction and the novels, mathematics and biology book are just seen as books.

Total number of books is:

N = Mathematics + Novel + Biology

N = 4+5+1

N = 10

The number of arrangement is:

10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1

10! = 3628800\ ways

(b):

If the mathematics books are together, there are 4! different  arrangements

If the novels are together, there are 5! different arrangements

Now, there are 3 bundles.

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This can be arranged in 3! ways.

Total number of arrangement is:

Total = 4! * 5! * 3!

Total = 4*3*2*1 * 5*4*3*2*1 * 3*2*1

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Which set of sides would make a right angle ?
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