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Serhud [2]
3 years ago
8

The height of 2 ball in meters is given by the quadratic equation y= -5+² +14t +3, where t is the time in seconds. After how man

y
seconds will the ball hit the ground?
Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer: after 3 seconds

when  the ball hit the ground => - 5t² + 14t + 3 = 0

⇔ (5t + 1)(t - 3) = 0

⇔ t = 3 or t = -1/5

but t  is a positive integer => t = 3

so the ball will hit the ground after 3 seconds

Step-by-step explanation:

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SOMEONE PLEASE ANSWER ASAP!! 55 POINTS!!
nadezda [96]

Answer:

EG = 16 and FH =22

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other

so 2a  = 3b+2

and 2a+3 = 6b-1

We know have a system of equations to solve

2a  = 3b+2

 2a+3 = 6b-1

Subtract 3 from each side

2a+3-3 = 6b-1-3

2a = 6b -4

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3b+2 = 6b-4

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3b-3b+2 = 6b-3b-4

2 = 3b-4

Add 4 to each side

2+4 = 3b-4+4

6 = 3b

Divide by 3

6/3 = 3b/3

2 =b

We want to find a

2a  = 3b+2

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2a = 3(2) + 2

2a = 6+2

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2a/2 =8/2

a = 4

Now that we know a and b

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    = 2(4) +3 +6(2)-1

    = 8+3+12-1

   = 23-1

  = 22

4 0
3 years ago
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