OMG U GO TO MY SCHOOL!!!! What grade r u in?!?!
It might be a little late BUT the answer is B
Answer:
sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21
Step-by-step explanation:
During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.
50 m/s is going to be 180 km/h or 3 km/s.
50 / 1000 = 0.05
0.05 x 60 = 3 kilometers a minute.
3 x 60 = 180 kilometers an hour.
50 m/s divided by 1 kilometer = 0.05 kilometers a second. You then multiply it by 60 to get it in minutes, and then 60 again to get it in hours. because their are 3600 seconds in an hour. So you could divide 50 meters per second by 1000 meters or 1 kilometer and then multiply it by 3600 seconds to get 180 kilometers an hour.
0 Pretend that is theta XD
cot 0 = 
Find tan 0.
tan 0 = 
tan 0 = 
tan 0 = 
cot 0 =
cot 0 = 
Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)
cot 0 = 
cot 0 = 
Multiply √5 to the numerator and the denominator
cot 0 = 
cot 0 = 
