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zlopas [31]
4 years ago
5

Juan and Alex are both saving money for college. Juan saves $150 per month and currently has $2000 in the bank. Alex saves $250

per month and has only $1000 in the bank. Not counting the interest they will earn, how many months will it take until both boys have saved the same amount of money?
• Let m represent the # of months it takes Juan and Alex to save the same amount of money
• Let A represent the amount of money they will have after m months.
Mathematics
1 answer:
Reika [66]4 years ago
5 0
Let, m = months they take.

So, 2000 + 150m = 1000 + 250m
2000 - 1000 = 250m - 150m
100m = 1000
m = 1000 / 100
m = 10

Now, Money after 10th months = 2000 + 150(10) = $3500

Hope this helps!
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For every 6 boys in the class there are 4 girls. If there are 42 more boys than girls, how many girls are there in the class?
Mandarinka [93]

Answer:

28

Step-by-step explanation:

you would divide 42 by 6 which is 7 and than multiply 7 by 4 which would get you 28

4 0
3 years ago
Read 2 more answers
2. The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4.5. Suppose we going t
stiv31 [10]

Answer:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable who represent the score of golfers. We select a sampel size of 81.

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

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3 years ago
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Answer:

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Step-by-step explanation:

y - 3 = 2 (x - 4)

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y = 2x - 5

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Andrew [12]

Answer:

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Step-by-step explanation:

hope it will help you

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Step-by-step explanation: Hopefully this helps! :)

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