Perpendicular distance i believe
Y - x = 154
let z = xy = x(154 + x) = x^2 + 154x
we need to find the minimum value of z
z' = 2x + 154 which = zero for minm or maxm value
x = -77 and y = 154 -77 = 77
so the 2 numbers are -77 and 77
<h2>
Answer:</h2>
<u>Area</u> = 2(1/2 × 5 × 5) + 20 × 10
= 2 × 12.5 + 200
= 25 + 200
= 225ft².
Answer:
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