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3 years ago

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A jar contains 2 red marbles numbered 1 to 2 and 4 blue marbles numbered 1 to 4. A marble is drawn at random from the jar. Find

the probability of the given event. (a) The marble is red Your answer is : ------------------ (b) The marble is odd-numbered Your answer is : --------------------- (c) The marble is red or odd-numbered Your answer is : ------------------------- (d) The marble is blue or even-numbered Your answer is : ------------------------------

1 answer:

Marina86 [1]3 years ago

3 0

Answer: Again I ask.... What?

Step-by-step explanation:

You might be interested in

14. Find the Error Hiroshi is determining -42 – (-37). Find his

vaieri [72.5K]

Answer:

Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.

Step-by-step explanation:

we have

Hiroshi's work

$42-(-37)=42-37=5$

Remember that

a negative number is just a positive number multiplied by -1

and (-1)(-1)=+1

so

Correct work

$42-(-37)$

$42-(-1)(37)$

$42-(1)(-1)(37)$

$42+(-1)(-1)(37)$

$=42+37=79$

therefore

Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.

3 0

2 years ago

Luanne made a photocopy of a drawing of a rectangle. The original drawing was 4.5 inches wide and 6 inches long. The copy was 6.

san4es73 [151]

The scale factor is:
$6,75/4,5 = 9/6 = 1,5$

So you divide the corresponding lengths and the ratio you get is the scale factor. Hope it helps!

8 0

3 years ago

The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had th

Maru [420]

Student 4 has the largest percent error.

Step-by-step explanation:

The percent error of a measurement is given by

$p=\frac{|x-x_{true}|}{x_{true}}\cdot 100$

where

x is the value of the measurement

$x_{true}$ is the actual value

For student 1:

$x=49\\x_{true}=50$

Percent error:

$p=\frac{|49-50|}{50}\cdot 100=0.02\cdot 100=2\%$

For student 2:

$x=25.5\\x_{true}=25$

Percent error:

$p=\frac{|25.5-25|}{25.5}\cdot 100=0.0196\cdot 100 = 1.96\%$

For student 3:

$x=7.5\\x_{true}=8$

Percent error:

$p=\frac{|7.5-8|}{8}\cdot 100=0.0625\cdot 100 = 6.25\%$

For student 4:

$x=2.1\\x_{true}=1.6$

Percent error:

$p=\frac{|2.1-1.6|}{1.6}\cdot 100=0.3125\cdot 100 = 31.25\%$

So, student 4 has the largest percent error.

Learn more about errors:

brainly.com/question/2764830

#LearnwithBrainly

4 0

3 years ago

A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain

svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

$P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633$

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

$\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55$

The mean of this distribution is:

$\mu=np=10*0.6=6$

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

$LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8$

The probability of having between 4 and 8 customers choosing the oversize version is:

$P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989$

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

$P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328$

7 0

3 years ago

Bob recorded the number of hours each person watched TV in a week. He then organized the information in a frequency table.

seraphim [82]

Answer:

yque ha haceqr ailluey

Step-by-step explanation:

6 0

3 years ago