Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b

Question

kondaur [170]

4 years ago

15

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b

, what is the value of b?

Mathematics

1 answer:

Vlada [557] · Answer 1 · 2022-01-02T16:38:26+03:00

Vlada [557]4 years ago

3 0

The value of b is -21. To find the slope of the line use the slope formula: $\frac{y^2 - y^1}{ x^{2} - x^1}$ . The slope is -4. Then you plug in one coordinate to find the value of b.