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1 year ago

See image attached below

Mathematics

1 answer:

natali 33 [55]1 year ago

6 0

Answer:

x = 35

Step-by-step explanation:

The figure has 6 angles so the figure is a convex hexagon

The sum of interior angles in a convex hexagon is equal to 720

4x - 5 + 117 + 3x - 3 + 3x + 6 + 118 + 4x -3 = 720 add like terms

14x + 230 = 720 subtract 230 from both sides

14x = 490 divide both sides by 14

x = 35

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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

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A pickup truck carrying 10 to the 3rd power identical bricks weighs 6,755 pounds. If the empty truck weighs 6,240 pounds, what i

Aleks04 [339]

Answer:

The answer is that each brick weights .515 pounds.

Step-by-step explanation:

10 to the 3rd power is 10^3 = 1000 bricks.

The weight of the full truck minus the weight of the empty truck is the weight of the bricks:

6755 - 6240 = 515 pounds of bricks

Pounds per brick:

515 / 1000 = .515 pounds per brick.

Hope this helps! Have a great day!

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Answer:

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Step-by-step explanation:

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