The perimeter in this case is:
y + 2x = 5000
The area is:
A = x * y
We rewrite the area:
A = x * (5000-2x)
A = 5000x-2x ^ 2
We derive:
A '= 5000-4x
We equal zero and clear x:
0 = 5000-4x
4x = 5000
x = 5000/4
x = 1250
We look for the other dimension:
y = 5000-2x
y = 5000-2 (1250)
y = 5000-2500
y = 2500
Then, the area will be:
A = (2500) * (1250)
A = 3125000 m ^ 2
Answer:
The largest area that can be enclosed is:
A = 3125000 m ^ 2
Answer:
B. It can only be used for one variable at a time
Step-by-step explanation:
Simulation can accommodate multiple variables at a time. The variables could be constraints such as time, amount, quantity, duration. A range of expected values must either be developed or provided for the variables before simulation models can then be applied to these ranges to generate a distribution of NPVs.
It would be multiplication and subtraction
4(x-3)
four times
( the difference of a number “x” and three)
difference means subtraction every time.
6 hours unless there is a day in there.
Answer:
x <- x - 5
Step-by-step explanation: