Which polynomial is written in standard form for the polynomial 4x^2+x^5-12+6x

Determine the perimeter of triangle AGN.

Harman [31]

Answer:

150

Step-by-step explanation:

The perimeter of a triangle is defined or given as the summation of all its 3 sides.

Mathematically,

The perimeter of a Triangle = Side A + Side B + Side C

In the above question, we are to find the perimeter of Triangle AGN.

In the diagram , we have an inscribed circle of RTE

Therefore these values are given in the question.

Side AR = 35

Side RG = 21

Side EN = 19

We have an inscribed Triangle in the question with its side touching the Triangle. This means we have lines that are tangent. Hence we have,

Side EG = Side RG = 21

Side TN = Side EN = 19

Side AT = Side AR = 35.

Therefore, The Perimeter of Triangle AGN = Side AT + Side AR + Side TN + Side EN + Side EG + Side RG

= 35 + 35 + 19 + 19 + 21 + 21

= 150

The perimeter of Triangle AGN is 150

3 0

4 years ago

Someone help me with this please

Nina [5.8K]

The answer is 3,240,000

4 0

4 years ago

A water tank holds 944 gallons but is leaking at a rate of 5 gallons per week. A second water tank holds 1,180 gallons but is le

podryga [215]

Answer:

59

Step-by-step explanation:

The equation is

944 - 5x = 1180 - 9x

Notice what is being said. You start with 944 gallons and take off 5 per week

You also start with 1180 gallons and take on 9 per week.

You want to know when the two are equal. The second tank is larger, but it leaks more. That's what's going to bring about equality.

Add 9x to both sides

944 - 5x + 9x = 1180

944 + 4x = 1180

Subtract 944 from both sides.

4x = 1180 - 944

4x = 236

Divide by 4

x = 236/4

x = 59 weeks

8 0

3 years ago

PLZ HELP WITH THIS QUESTION PLZ CORRECT ANSWERS!!! LOVE YOU THNX

iogann1982 [59]

Answer:

1) The value of x= 0.0642

2) $sin\theta=\frac{P}{H}=\frac{24}{25}$

$cos\theta=\frac{B}{H}=\frac{7}{25}$

$tan\theta=\frac{P}{B}=\frac{24}{7}$

$cosec\theta=\frac{H}{P}=\frac{25}{24}$

$cot\theta=\frac{B}{P}=\frac{7}{25}$

Step-by-step explanation:

1) Given : A right angle triangle with sides x and 10 and angle is 50°

To find : Value of x

Solution : Since, it is a right angle triangle

Therefore, we apply $cos\theta=\frac{B}{H}$

Where Base = x, Hypotenuse= 10, angle = 50°

$cos(50)=\frac{x}{10}$

$0.642=\frac{x}{10}$

$0.0642=x$

The value of x= 0.0642

2) Given : $sec\theta=\frac{25}{7}$

To find : Value of $sin\theta,cos\theta,tan\theta,cosec\theta,cot\theta$

Solution : We have given $sec\theta=\frac{25}{7}$

$sec\theta=\frac{H}{B}$

so, B= 7 , H=25

By Pythagoras theorem,

$H^2=P^2+B^2$

$25^2=P^2+7^2$

$625-49=P^2$

$\sqrt{576}=P^2$

$P=24$

Now, P=24, B=7, H=25

$sin\theta=\frac{P}{H}=\frac{24}{25}$

$cos\theta=\frac{B}{H}=\frac{7}{25}$

$tan\theta=\frac{P}{B}=\frac{24}{7}$

$cosec\theta=\frac{H}{P}=\frac{25}{24}$

$cot\theta=\frac{B}{P}=\frac{7}{25}$

5 0

3 years ago

Three signals that beep.

notka56 [123]

Answer:

The number of times signal a beeps in 1 hour = 144 times

The number of times signal b beeps in 1 hour = 120 times

The number of times signal c beeps in 1 hour = 36 times

The number of times three signals bee in one hour = 12 times

Step-by-step explanation:

The given parameters are;

The period for each signals beep are;

Signal a beeps every 25 seconds

Signal b beeps every 30 seconds

Signal c beeps every 100 seconds

Therefore, in one hour, signal a will beep 1× 60 × 60/25 = 3600/25 = 144 times

In one hour, signal b will beep 1×60×60/30 = 3600/30 = 120 times

In one hour, signal c will beep 1×60×60/100 = 3600/100 = 36 times

Therefore, we have;

The number of times signal a beeps in 1 hour = 144 times

The number of times signal b beeps in 1 hour = 120 times

The number of times signal c beeps in 1 hour = 36 times

From Excel, we can see that the three signals beep the same time at 300, 600, 900, 1200, 1500, 1800, 2100, 2400, 2700, 3000, 3300, and 3600

The number of times three signals bee in one hour = 12 times

8 0

3 years ago