The answer is 15x good luck on your homework buddy
<span>A.5/4 is your answer.
It is not possible for you to have a greater amount of chance than a 100% chance (which will definitely happen).
hope this helps</span>
Volume of the box= <span>56 cubic inches
let x is the length, then
width =</span><span>2 inches shorter than its length = x - 2
</span>height = <span>3 inches taller than its length = x+3
Volume = length x width x height
56 = x x (x-2) x (x+3)
56 = (x</span>² -2x)(x+3)
56 = x³ +3x² -2x² - 6x
56 = x³ + x² -6x
x³+x²-6x-56 = 0
using the rational root theorem and factoring the polynomial;
(x-4)(x² +5x +14) = 0
from here;
x-4 = 0
x = 4
So, length = 4 inches
width = x - 2 = 4 -2 = 2 inches
length = x + 3 = 4 + 3 = 7 inches
volume = l x w x h = 4 x 2 x 7 = 56
Answer:
Height of flagpole before it fell = 5.15 m
Step-by-step explanation:
Given:
Height of remain pole (p) = 1.7 m
Distance from base (b) = 3 m
Find:
Height of flagpole before it fell
Computation:
Using Pythagorean theorem
H = √ p² + b
Length of broken part = √ 1.7² + 3²
Length of broken part = √ 2.89 + 9
Length of broken part = √ 11.89
Length of broken part = 3.45 (Approx)
Height of flagpole before it fell = Length of broken part + Height of remain pole
Height of flagpole before it fell = 3.45 + 1.7
Height of flagpole before it fell = 5.15 m
