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2 years ago

−1 + 6 = 5 + 8 + 4 Group of answer choices 10 1 -2 - 3 witch one

Mathematics

2 answers:

Sladkaya [172]2 years ago

5 0

Answer:

Step-by-step explanation:

$x = 5 + 8 + 4 - 6 + 1$

$x = 17 - 6 + 1$

$x = 11 + 1$

$x = 12$

Sav [38]2 years ago

4 0

If your doing linear algebra, it would be -3.4 which is rounded down to -3

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Help!! I will mark Brainliest!! Please show work! :) Thank You.

SSSSS [86.1K]

Answer:

The center is (20, 0.05) radius = 9

Step-by-step explanation:

The center is (20, 0.05) radius = 9

from the general form of the equation:

(x - h)^2 + (y - k)^2 = r^2

we see that r^2 = 81

so r = 9

3 0

3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$