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3 years ago

What are the different types of triangles ?

Mathematics

2 answers:

sp2606 [1]3 years ago

6 0

Right-angle triangle

equilateral triangle

isosceles triangle

scalene triangle

jarptica [38.1K]3 years ago

6 0

isosceles. scalene Equilateral

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Need help asap! Fill in the blank by entering just a number…

daser333 [38]

Answer:

x = 6

Step-by-step explanation:

CT is a median, which means it divided AB into two equal parts so we can write the following equation:

7x + 9 = 5x + 21 transfer like terms to the same side of the equation

7x - 5x = 21 - 9 do the extraction

2x = 12 divide both sides by 2

x = 6

6 0

1 year ago

Solve for d. d+ 4 = 16.21 d=

lutik1710 [3]

Answer:

d = 12.21

Step-by-step explanation:

1) Subtract 4 from both sides.

d = 16.21 - 4

2) Simplify 16.21 - 4 to 12.21.

d = 12.21

Check the answer!

⇒ d + 4 = 16.21

1. Let d = 12.21.

⇒ 12.21 + 4 = 16.21

2. Simplify 12.21 + 4 to 16.21

16.21 = 16.21

Done!

Thanks,

Eddie

8 0

11 months ago

2a) Solve using substitution.

Tcecarenko [31]

First things first, write out your equation without the substitution.

2x+ 2y= 10

Now, put in the substitution.

2x+ 2• 2= 10

Combine like terms.

2x+ 4= 10

Now that your equation it simplified, you need to reverse the problem and put everything on the other side.

2x+ 4= 10
- 4 - 4
2x = 6

2x=6
— —
2 2

X= 3

So the final answer is x=3

8 0

2 years ago

What is the completely factored form of d4 -8d2 + 16

irinina [24]

According to Vieta's Formulas, if $x_1,x_2$ are solutions of a given quadratic equation:

$ax^2+bx+c=0$

Then:

$a(x-x_1)(x-x_2)$ is the completely factored form of $ax^2+bx+c$ .

If choose $x=d^2$ , then:

$\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm \sqrt{64-64} }{2}=4$

So, according to Vieta's formula, we can get:

$x^2-8x+16=(x-4)(x-4)= (x-4)^2$

But $x=d^2$ :

$d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2$

8 0

2 years ago

if the graph of a quadratic function intersects with the x axis two times, how many solutions are there to the equation when set

konstantin123 [22]

Hello there!

This is a conceptual question about quadratic functions.

Remember that a solution of ANY function is where it intersects the x-axis, so if the quadratic function intersects the x-axis TWO times, this means that there are TWO real solutions.

Here's a list of things to remember that will help you out for quadratic functions...
•if a quadratic function intersects the x-axis twice, it has two real solutions.
•if a quadratic function intersects the x-axis once, it has one real solution and one imaginary solution.
•if a quadratic function intersects the x-axis zero times, it has zero deal solutions and two imaginary solutions.

Please NOTE: If you want to know how many solutions a polynomial function has, look at it's highest exponent. If it is 2, then it has 2 solutions whether they be real or imaginary. If it is 3, then it has 3 solutions.

Also, if one of the factors are the same for a polynomial function, the way it hits the x-axis changes! This is just some extra information to help you in the long run!

I hope this helps!
Best wishes :)

8 0

3 years ago