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ololo11 [35]
3 years ago
14

Suppose 49,000 people have tickets for a basketball game. Arena A seats 40,000 people. Arena B seats 50,000. Which arena should

host the game? Explain how you would decide.
Mathematics
1 answer:
sp2606 [1]3 years ago
8 0

Arena B should host the game

Step-by-step explanation:

Arena A has 40000 seats

Arena B has 50000 seats

The people that have the tickets are 49000.

As we can see that 40000<49000 so Arena A is not suitable for hosting the game because 9000 people will be left.

For Arena B, 50000>490000, which means that 49000 people can easily be seated there. So,

Arena B should host the game

Keywords: Comparison, Operators

Learn more about comparison at:

  • brainly.com/question/2116906
  • brainly.com/question/2131336

#LearnwithBrainly

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What is 49/179 simplified
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Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are
Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

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4 years ago
Rudolph and the other reindeer are pulling Santa's sleigh that has a mass 1
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
And, S2
dangina [55]

<u>Correct Question</u>

In the table shown, the sum of each row is shown to the right of the row and the sum of each column is shown below the column. What is the value of L?

\left|\begin{array}{c|c|c|c}-&-&-&-\\J&K&J&5\\K&K&L&13\\L&J&L&15\\-&-&-&-\\11&7&15\end{array}\right

Answer:

L=7

Step-by-step explanation:

From the first row: 2J+K=5

Therefore: K=5-2J

From the second column, 2K+J=7

Substitute K derived above into 2K+J=7

2K+J=7

2(5-2J)+J=7

10-4J+J=7

-3J=7-10

-3J=-3

J=1

Recall: K=5-2J

K=5-2(1)=3

K=3

From the third column, J+2L=15

1+2L=15

2L=15-1=14

L=7

Therefore, the value of L=7

CHECK:

\left|\begin{array}{c|c|c|c}-&-&-&-\\1&3&1&5\\3&3&7&13\\7&1&7&15\\-&-&-&-\\11&7&15\end{array}\right

4 0
3 years ago
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