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Rufina [12.5K]
2 years ago
13

(8.11×107)–(4.3×107)

Mathematics
2 answers:
wlad13 [49]2 years ago
5 0

Step-by-step explanation:

(8.11×107)–(4.3×107)

According to the concept of BODMAS,

<em>A</em><em>t </em><em>first</em><em> we</em><em> </em><em>should</em><em> </em><em>solve</em><em> </em><em>the </em><em>trems</em><em> </em><em>in </em><em>the </em><em>bracket</em><em>,</em>

867.77-460.1

<em>Now,</em><em> </em><em>we </em><em>should</em><em> </em><em>subtract </em><em>them,</em>

<em>4</em><em>0</em><em>7</em><em>.</em><em>6</em><em>7</em>

stira [4]2 years ago
4 0
Put it in a calculator bro
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3 years ago
Find the sum. 64 + (-15)
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) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

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Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

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Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

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\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
3 years ago
\frac{5}{9}+\frac{y}{3}<br> Welp
Sergeeva-Olga [200]
The answer is 3y+5/9.
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