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Alexeev081 [22]
3 years ago
9

Can fiurge this out

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0

Answer:

i want to help but i don't know if am right. but it has to be soccer

Step-by-step explanation:

jeka57 [31]3 years ago
3 0

Answer:

soccer

Step-by-step explanation:

rover

r=s v=cc

soccer

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Which equation is in point-slope form for the given point and slope?
faust18 [17]

Answer: y-7 = 4(x+3), choice B

============================================

Point slope form is generally

y-y1 = m(x-x1)

we have m as the slope and (x1,y1) as the point this line goes through. In this case,

m = 4

(x1,y1) = (-3,7) so x1 = -3 and y1 = 7

So,

y-y1 = m(x-x1)

y - 7 = 4(x - (-3))

y - 7 = 4(x + 3)

which is why choice B is the answer

6 0
4 years ago
Read 2 more answers
the boiling of jet fuel is 390f. rounded t the nearest degree, what is the temperature in degrees celsius? where c represents de
e-lub [12.9K]
390f = 198.889c
Hope this helps! 
7 0
3 years ago
HELP ASAP PLEASE!!! worth 20 points!!
lukranit [14]
No, because the height of the boat is 2.1+8.7=10.8
after the boat is lifted, it’s 1.3 feet above the ground in which is addition to the total height the boat will take up. 10.8+1.3=12.1 feet.
4 0
4 years ago
2x+ 1/X-3+x/x-3+4/x-3
yaroslaw [1]
Answer is below lmk if it’s correct or wrong

3 0
3 years ago
To aid in sea navigation, Little Gull Island Lighthouse shines a light from a height of 91 feet above sea level with an unknown
algol13

Answer:

\approx 6^\circ

Step-by-step explanation:

Given that:

Little Gull Island Lighthouse shines a light from a height of 91 feet above the sea level.

The angle of depression is unknown.

Distance of the point at sea surface from the base of lighthouse is 865 ft.

This situation can be modeled or can be represented as the figure attached in  the answer area.

The situation can be represented by a right angled \triangle ABC in which we are given the base and the height of the triangle.

And we have to find the value of \angle BAD \ or \ \angle C (Because they are the internal vertically opposite angles).

Using tangent ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanC = \dfrac{AC}{BC}\\\Rightarrow tanC = \dfrac{91}{865}\\\Rightarrow tanC = 0.105\\\Rightarrow \angle C \approx 6^\circ

Therefore, the angle of depression is: \approx 6^\circ

7 0
3 years ago
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