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3 years ago

Math vocabulary what is The definition of increasing and decreasing functions

1 answer:

8 0

Increasing function is any function whose value increases with respect to an increase in the variables.

Decreasing function is any function whose values are decreases with respect to an increase in the variables.

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Ok maths experts ,here is your trigonometric question

EleoNora [17]

Answer:

Step-by-step explanation:

i don't take trig :/

6 0

3 years ago

Can somebody please find the answer I will mark brainliest

mash [69]

Answer:

1= 102°,3=78°,4=102°

5=102°,6=78°,7=78°,8=102°

Step-by-step explanation:

6 0

3 years ago

In the figure, ∆BAT ≅ ∆CAT. Which statement is not true by CPCTC? ∠CAB ≅ ∠SAB ∠CAS ≅ ∠BAS

Studentka2010 [4]

Answer:

∠CAB ≅ ∠SAB is not true

Step-by-step explanation:

CPCTC means id ABC = XYZ, than A=X, AB=XY, C=Z and so on. Basically the number numbers that come in the same order as the other one is equal.

So ∠CAS ≅ ∠BAS is true but ∠CAB ≅ ∠SAB is not.

Hope this helps. If you have any follow-up questions, feel free to ask.

Have a great day! :)

8 0

3 years ago

What is the quotient?

Ugo [173]

Answer:

I got 4e+12 which is d

I think

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Tomato as a taste modifier. Miraculin—a protein naturally produced in a rare tropical fruit—has the potential to be an alternati

telo118 [61]

Answer:

a) 0.033

b) 0.468

c) 100

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 105.3

Standard Deviation, σ = 8

The amount x of miraculin produced (measured in micro-grams per gram of fresh weight) had a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(x > 120)

$P( x > 120) = P( z > \displaystyle\frac{120 - 105.3}{8}) = P(z > 1.8375)$

$= 1 - P(z \leq 1.8375)$

Calculation the value from standard normal z table, we have,

$P(x > 120) = 1 - 0.967 = 0.033 = 3.3\%$

b) P(x between 100 and 110)

$P(100 \leq x \leq 110) = P(\displaystyle\frac{100 - 105.3}{8} \leq z \leq \displaystyle\frac{110-105.3}{8}) = P(-0.6625 \leq z \leq 0.5875)\\\\= P(z \leq 0.5875) - P(z \leq -0.6625)\\= 0.722 - 0.254 = 0.468 = 46.8\%$

$P(100 \leq x \leq 110) = 46.8\%$

c) P(x < a) = 0.25

$P( x \leq a) = P( z \leq \displaystyle\frac{a - 105.3}{8}) = 0.25$

Calculation the value from standard normal z table, we have,

$P( z \leq -0.674) = 0.25$

$\displaystyle\frac{x - 105.3}{8} = -0.674\\\\x = -0.674\times 8 + 105.3 = 99.908 \approx 100$

3 0

3 years ago