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NikAS [45]
3 years ago
5

The admission prices for a small fair are $1.50 for children and $4.00 for adults. In one day there was $5050 collected. If we k

now that 2100 children paid admission, find the number of adults that paid admission.
Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer: 475 adults paid admission

Step-by-step explanation:

1.50c+4a=5050 (1.50 per child and 4 per adult)

1.50(2100)+4c=5050 (2100 children times 1.5 each)

3130+4a=5050

4a=1900

a=475

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Answer/Step-by-step explanation:

✔️The rate of change can be calculated using the coordinates of any two points on the graph. Let's use (2, 60) and (3, 75):

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Rate of change (m) = 15

✅In the context of this situation, the rate of change can be interpreted to be the additional fee per class. Thus, an additional fee per class cost $15.

✔️Initial value is the same as the y-intercept.

To find the y-intercept (b), substitute m = 15, x = 2, and y = 60 into y = mx + b.

Thus:

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The initial value/y-intercept = $30

✅In this context, $30 is the start-up fee to cover art supplies.

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3 years ago
Construction worker’s planned to secure a tall pole using two cables attached to the pole at a point 12 m above the ground as sh
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Answer:(24+12\3)m

Step-by-step explanation:

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3 years ago
-15=-4m+5<br><br>8n+7=31<br><br>-10=10(k-9)
Korolek [52]
-15=-4m+5\ \ \ |both\ sides\ /+4m\\\\4m-15=5\ \ \ \ |both\ sides\ /+15\\\\4m=20\ \ \ \ |both\ sides\ /:4\\\\\underline{\underline{m=5}}

=========================================================

8n+7=31\ \ \ \ |both\ sides\ /-7\\\\8n=24\ \ \ \ |both\ sides\ /:8\\\\\underline{\underline{n=3}}

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10(k-9)=-10\ \ \ \ |both\ sides\ /:10\\\\k-9=-1\ \ \ \ |both\ sides\ /+9\\\\\underline{\underline{k=8}}
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3 years ago
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Hi there!

So -5 1/2 + 7 3/4 is 
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3 years ago
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How many planes contain each line and point?
nikitadnepr [17]

There are infinite many planes that contain each line and point

<h3>How to determine the number of planes?</h3>

The given parameters are given as:

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