Answer:
Yes, look at the explanation:
Step-by-step explanation:
- Calculate how many miles a car can drive with 1 gallon: 285 miles ÷ 10 = 28.5 miles with one gallon
- Divide 500 by 28.5 to calculate how many gallons are needed: 500 ÷ 28.5 ≈ 17.543 - Therefore yes, it is possible because the car uses about 17.543 gallons of gasoline for 500 miles.
-9x^3-72x^2+36=3x^3+x^2-3x+8 Add 9x^3 to both sides.
-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8 Add 72x^2 to both sides
36 = 12x^3 + 73x^2 - 3x + 8 Subtract 36 from both sides.
0 = 12x^3 + 73x^2 - 3x - 28
It does factor, but it is not very nice.
(x + 6.06)(x - 6.09)(x + 0.632)
If there is any kind of error please report it in a note below.
Answer:
x/7<-3
x<-21
Step-by-step explanation:
x/7<-3
multiply the seven to get rid of x denominator
x<-21
Answer:
x = -2
y = -1
(-2, -1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 1
3x + 3y = -9
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 3x + 3(x + 1) = -9
- Distribute 3: 3x + 3x + 3 = -9
- Combine like terms: 6x + 3 = -9
- Isolate <em>x</em> term: 6x = -12
- Isolate <em>x</em>: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x + 1
- Substitute in <em>x</em>: y = -2 + 1
- Add: y = -1
<u>Step 4: Graph systems</u>
<em>Check the solution set.</em>
Answer:
8 and -4
Step-by-step explanation:
8*-4=-32
8+(-4)=4