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nasty-shy [4]
3 years ago
9

Simplifying

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0
I am just typing to get points sorry I need them bad pleasebunderstand
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Answer:

I am not able to answer your question because I am unsure of what to solve for. :/

Step-by-step explanation:

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3 years ago
Tori invests $1,500 into the stock market which earns 9% per year. In 20 years, how much will Tori's investment be worth if inte
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4 0
2 years ago
compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
1 year ago
What's 2,000 times 4,000???
AnnyKZ [126]

Answer:

8000000

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Help will give crown
frosja888 [35]

Answer:

This means our slope is equal to \frac{6}{4}.

Step-by-step explanation:

Your ordered pairs are:

(-4, -4) and (0, 2)

To solve for the slope, we must use slope formula.

\frac{y2-y1}{x2-x1}

Substitute:

\frac{2+4}{0+4}

Solve:

\frac{6}{4}

This means our slope is equal to \frac{6}{4}.

Hope this helped. :)

4 0
3 years ago
Read 2 more answers
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