Can someone help me with this
1 answer:
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Remember
(ab)/(cd)=(a/c)(b/d)
and
1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=
=
=
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
</span>
(ab)/(cd)=(a/c)(b/d)
and
1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
</span>
Answer:
He have <u>47</u> ducks and <u>7</u> cows.
Step-by-step explanation:
Given:
Farmer Jones raises ducks and cows.
He looks out his window and sees 54 animals with a total of 122 feet.
Now, to find the each type of animal he have.
Let the number of ducks be
And the number of cows be
So, total number of animals are:
....( 1 )
As, the feet of cows are 4 and ducks are 2.
Now, the total number of feet are:
Substituting the value of from equation (1) we get:
<em>Subtracting both sides by 108 we get:</em>
<em>Dividing both sides by 2 we get:</em>
<em>The number of cows = 7.</em>
Now, to get the number of ducks we substitute the value of in equation (1):
<em>The number of ducks = 47.</em>
Therefore, he have 47 ducks and 7 cows.