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LiRa [457]
3 years ago
14

What is 12 ten thousand 8 thousands 14 hundreds 7 ones

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer:

Eight thousand fourteen hundred twelve and seven

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lesya [120]
The answer would be 26.25
3 0
3 years ago
10 points! Please help ASAP.
DerKrebs [107]
Answer: Yes
Explanation:
120 % = 1.2

If Maxine is correct, then she spent 1.2
times the hours she did homework than last week.
15 ⋅ 1.2 = 18.0 = 18

15 hours ⋅ 1.2 = 18.0 hours = 18 hours
Maxine is correct
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3 years ago
Cable company a increase their rates from 98 a month to 110.92 a month.what is the percents of increase?
Debora [2.8K]
So from 98 to 110.92 is just 12.92 extra bucks.

if we take 98 to be the 100%, what is 12.92 off of it in percentage?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
98&100\\
12.92&p
\end{array}\implies \cfrac{98}{12.92}=\cfrac{100}{p}\implies p=\cfrac{12.92\cdot 100}{98}
6 0
3 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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3 years ago
Cheng-Yu has been recording data based on her age and height, which can be seen in the scatter plot shown. Predict Cheng-Yu's he
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Answer:

53

Step-by-step explanation:

5 0
3 years ago
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