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2 years ago

PLEASE HELP MEEEEe jhchnthnht

Mathematics

1 answer:

Mars2501 [29]2 years ago

6 0

The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x

<h3>Which method can be used to find the equation of the perpendicular bisector?</h3>

The slope, <em>m</em>, of the line BC is calculated as follows;

m = (2 - 1)/(4 - (-2)) = 1/6

The slope of the perpendicular line to BC is -1/(1/6) = -6

The midpoint of the line BC is found as follows;

$\left( - 2 + \frac{4 - ( - 2)}{2}, \: 1 + \frac{2 - 1}{2} \right) = (1,\: 1.5)$

The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.

The equation of the perpendicular bisector in point and slope form is therefore;

(y - 1.5) = -6•(x - 1)

y - 1.6 = -6•x + 6

y = -6•x + 6 + 1.6 = 7.6 - 6•x

Which gives;

y = 7.6 - 6•x

Learn more about equations of perpendicular lines here:

brainly.com/question/11635157

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Answer:

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Answer:

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Step-by-step explanation:

first, find the slope

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(1, -9)

remember the equation for the slope

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insert given points

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remember, the equation of the line is

y = mx + b

where "m" is the slope

and "b" is the y-intercept

to find "b", you just have to plug in a point that is found on the line

we know that (-4, 6) and (1. -9) is found on the line, so let's just use (-4, 6) for this problem

y = mx + b

substitute in the slope of this line

y = -3x + b

now substitute in the given points

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