Question

PLEASE HELP MEEEEe jhchnthnht

Answer 1

The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x

Which method can be used to find the equation of the perpendicular bisector?

The slope, m, of the line BC is calculated as follows;

• m = (2 - 1)/(4 - (-2)) = 1/6

The slope of the perpendicular line to BC is -1/(1/6) = -6

The midpoint of the line BC is found as follows;

$\left( - 2 + \frac{4 - ( - 2)}{2}, \: 1 + \frac{2 - 1}{2} \right) = (1,\: 1.5)$

The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.

The equation of the perpendicular bisector in point and slope form is therefore;

(y - 1.5) = -6•(x - 1)

y - 1.6 = -6•x + 6

y = -6•x + 6 + 1.6 = 7.6 - 6•x

Which gives;

• y = 7.6 - 6•x

Learn more about equations of perpendicular lines here:

brainly.com/question/11635157

#SPJ1