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Vesna [10]
2 years ago
12

PLEASE HELP PLEASE!!

Mathematics
1 answer:
Rudik [331]2 years ago
3 0
The square root of 75 is 8.66, so it would be between 8 and 9
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when planning for a party one caterer recommends the amount or meat be at least 2 pounds less than 1/3 the total number of guest
IgorLugansk [536]

Answer:

Let x be the number of guest and y be the quantity of meat,

According to the question,

y\geq \frac{x}{3}-2

Since, the related equation of the above inequality,

y=\frac{x}{3}-2

Having x-intercept = (6,0),

y-intercept = (0,-2)

Also,'≥' shows the solid line,

Now, 0 ≥ 0/3 - 2  ( true )

Hence, the shaded region of above inequality will contain the origin,

Therefore, by the above information we can plot the graph of the inequality ( shown below ).

3 0
3 years ago
Read 2 more answers
I really need help with this. can someone please help me
Andreyy89
Michael owns a small paper company called Michael Scott Paper Co.  He has 5 clients and needs to sell them each a specific amount of paper.  They have each ordered 3 3/10 worth of boxes.  He has to find out how many paper boxes he has to sell and how much extra paper (in tenths) he has total.

IF you want to turn it into a question, add:

How many paper boxes is he selling?
5 0
3 years ago
Joe has read 140 pages of his 300 page book what percentage has he read please show work
Lostsunrise [7]
140/300=14/30
14/30=7/15
So 7/15 is _
46.6%
8 0
2 years ago
The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =
Dafna1 [17]

Answer:

a) L'(t) = 34.416*e^(-0.18*t)

b) L'(0) = 34 cm/yr , L'(1) =29 cm/yr , L'(6) =12 cm/yr

c) t = 10 year                                          

Step-by-step explanation:

Given:

- The length of fish grows with time. It is modeled by the relation:

                                   L(t) = 200*(1-0.956*e^(-0.18*t))

Where,

L: Is length in centimeter of a fist

t: Is the age of the fish in years.

Find:

(a) Find the rate of change of the length as a function of time

(b) In this part, give you answer to the nearest unit. At what rate is the fish growing at age: t = 0 , t = 1, t = 6

c) When will the fish be growing at a rate of 6 cm/yr? (nearest unit)

Solution:

- The rate of change of length of a fish as it ages each year  can be evaluated by taking a derivative of the Length L(t) function with respect to x. As follows:

                             dL(t)/dt = d(200*(1-0.956*e^(-0.18*t))) / dt

                             dL(t)/dt = 34.416*e^(-0.18*t)

- Then use the above relation to compute:

                            L'(t) = 34.416*e^(-0.18*t)

                            L'(0) = 34.416*e^(-0.18*0) = 34 cm/yr

                            L'(1) = 34.416*e^(-0.18*1) = 29 cm/yr

                            L'(6) = 34.416*e^(-0.18*6) = 12 cm/yr

- Next, again use the derived L'(t) to determine the year when fish is growing at a rate of 6 cm/yr:

                             6 cm/yr = 34.416*e^(-0.18*t)

                             e^(0.18*t) = 34.416 / 6

                             0.18*t = Ln(34.416/6)

                             t = Ln(34.416/6) / 0.18

                             t = 10 year

7 0
3 years ago
e movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answ
Nimfa-mama [501]

9514 1404 393

Answer:

  4·10 +4·5 = 6·12 -6·2

Step-by-step explanation:

Each outside factor multiplies each inside term.

  4(10 +5) = 6(12 -2)

  4·10 +4·5 = 6·12 -6·2

3 0
2 years ago
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