Answer:
2.5 hours
Step-by-step explanation:
We are given that
Original height of candle=5 in
Every hour candle loses =8% of 5 in=0.4
According to question
Subtract 4 from both sides we get
Divide by 0.4 on both sides
x=2.5 hours
Until the candle has been burning for at least 2.5 hours, the height of her candle will be more than four inches.
The price of one adult ticket is $ 11 and the price of one student ticket is $ 11
<h3><u>Solution:</u></h3>Given that , Mofor’s school is selling tickets to the annual dance competition.
Let the cost of one adult ticket be $m and the cost of one student tickets be $n.
On the first day of ticket sales the school sold 7 adult tickets and 6 tickets for a total of $143.
7m + 6n = 143 ------- eqn (1)
The school took in $187 on the second day by selling 4 adult tickets and 13 student tickets.
4m + 13n = 187 ------ eqn (2)
We have to find the price of an adult ticket and the price of a student ticket.
Now, let us solve the equations.
Multiply eqn 1 by 4
28m + 24n = 572 ----- eqn 3
Multiply eqn 2 by 7
28m + 91n = 1309 ---- eqn 4
Now subtract eqn 4 from eqn 3
28m + 24n = 572
28m + 91n = 1309
(- )--------------------------------------
– 67n = - 737
67n = 737
n = 11
Plug in n = 11 in eqn 1
7m + 66 = 143
7m = 143 – 66
m = 11
Hence, the cost of one adult ticket is $ 11 and cost of one student ticket is $11
5×4=20 is closer to 24.9344.
Let's try placing the decimals after the hundreds place.
It works.
There is more than one possibility.
Answer:
The expression is
Jake has in his wallet
Step-by-step explanation:
Let
x-----> the money that Jake has in his wallet
we know that
The expression that represent the situation is equal to
1) Jake has $100 of birthday money in his wallet
so
2) He spends $15 at Twistee Treat and $10 at Wawa
so
3) He finds a $20 bill on the ground
so
3) His friend borrows $40 from Jake
so
4) At home, Jake mows the lawn and earns $35
so