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jek_recluse [69]
3 years ago
10

Anyone please help ! Explain for brainlest

Mathematics
1 answer:
myrzilka [38]3 years ago
8 0

336square yards

Step-by-step explanation:

you times 24and14

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If the lengths of the legs of a right triangle are 3 and 10, what is the length of the hypotenuse?
sergejj [24]

Answer:

<h2>a = √109 or 10.44</h2>

Step-by-step explanation:

To find the hypotenuse we use Pythagoras theorem which is given by

a² = b² + c²

where a is the hypotenuse

So we have

a² = 10² + 3²

a² = 100 + 9

a² = 109

<h3>a = √109 or 10.44</h3>

Hope this helps you

8 0
4 years ago
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FREEEEEEEEEEEEEEEEEEEEEEE POINTS
V125BC [204]

Answer:

thx!!

Step-by-step explanation:

5 0
3 years ago
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Provide the first six terms of the following sequence:<br><br> t1=81 tn=1/3tn-1
Andrews [41]

We get tne n-th term with: tn=1/3tn-1

We know that the first term is t1=81, so 81=1/3t*1-1

81=1/3t-1

82=1/3t

82*3t=1

3t=1/82

t=1/82*3=1/246

The second term is: 1/

2*(1/246)*2)-1

We get the third term by replacing n with 3 and so on...

8 0
3 years ago
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the participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men an
Nostrana [21]

Answer:

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

Step-by-step explanation:

The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men and women

That is probability of participants of television quiz of equal numbers of men and women that is 50 %of men and 50% of women.

p = 50/100 = 1/2

q = 1-p = 1 - 1/2 = 1/2

n =10

we will use binomial distribution p(x =r) = n_{cr} p^{r} q^{n-r}

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = P(x=0)+P(x=1)+P(x=2)

          = 10_{c0} \frac{1}{2} ^{0} (\frac{1}{2}) ^{10-0}+ 10_{c1} \frac{1}{2} ^{1} (\frac{1}{2}) ^{10-1   \\   + 10_{c2} \frac{1}{2} ^{2} (\frac{1}{2}) ^{10-2

          by using formula n_{cr} =\frac{n!}{(n-r)!r!}

on simplification we get

     = 10_{c0}  (\frac{1}{2}) ^{10}+ 10_{c1} (\frac{1}{2}) ^{10) + 10_{c2} (\frac{1}{2}) ^{10)

    = 1  (\frac{1}{2}) ^{10}+ 10(\frac{1}{2}) ^{10)+45  (\frac{1}{2}) ^{10}

  = \frac{56}{1024} = 0.0546

<u>Conclusion</u>:-

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

8 0
3 years ago
If 3x+1=-8, What is the value of (x+2)3?<br> a -1<br> b 1<br> c 8<br> d 125
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C jj NBC uvyg tvhas tvtcrxj try CB hmm gn jk VM I’m
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