Which expression is equivalent to 2x ^ 2 - 2x + 77 ? (4x + 1.2) + (2x ^ 2 - 6x + 5) (x ^ 2 - 5x + 13) + (x ^ 2 + 3x - 6) (4x ^ 2

Question

ankoles [38]

3 years ago

13

Which expression is equivalent to 2x ^ 2 - 2x + 77 ? (4x + 1.2) + (2x ^ 2 - 6x + 5) (x ^ 2 - 5x + 13) + (x ^ 2 + 3x - 6) (4x ^ 2

- 6x + 11) + (2x ^ 2 - 4x + 4) (5x ^ 2 - 8x + 120) + (- 3x ^ 2 + 10x - 13)

Mathematics

1 answer:

Firdavs [7] · Answer 1 · 2022-08-21T21:59:10+03:00

Answer:

None of the answers provided are equivalent

Step-by-step explanation:

To solve it would be best to simplify each of the expressions you have listed by combining like terms all the x^2 terms have been bolded, the x terms italicized, and the constant terms are underlined

(4x + 1.2) + (2x ^ 2 - 6x + 5) = 2x ^ 2 - 6x + 6.2

(x ^ 2 - 5x + 13) + (x ^ 2 + 3x - 6) = 2x^2 -2x +7

(4x ^ 2 - 6x + 11) + (2x ^ 2 - 4x + 4) = 6x^2 -10x +15

(5x ^ 2 - 8x + 120) + (- 3x ^ 2 + 10x - 13) = 2x^2 + 2x + 107