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ankoles [38]
3 years ago
13

Which expression is equivalent to 2x ^ 2 - 2x + 77 ? (4x + 1.2) + (2x ^ 2 - 6x + 5) (x ^ 2 - 5x + 13) + (x ^ 2 + 3x - 6) (4x ^ 2

- 6x + 11) + (2x ^ 2 - 4x + 4) (5x ^ 2 - 8x + 120) + (- 3x ^ 2 + 10x - 13)
Mathematics
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

None of the answers provided are equivalent

Step-by-step explanation:

To solve it would be best to simplify each of the expressions you have listed by combining like terms all the x^2 terms have been bolded, the x terms italicized, and the constant terms are underlined

(<em>4x</em> <u>+ 1.2</u>) + (2x ^ 2 <em>- 6x</em> <u>+ 5</u>) = 2x ^ 2 <em>- 6x</em> <u>+ 6.2</u>

(x ^ 2 <em>- 5x</em> +<u> 13</u>) + (x ^ 2 <em>+ 3x </em><u>- 6</u>) = 2x^2 <em>-2x </em><u>+7</u>

(4x ^ 2<em> - 6x</em> <u>+ 11</u>) + (2x ^ 2<em> - 4x</em><u><em> </em></u><u>+ 4</u>) = 6x^2 -<em>10x </em><u>+15</u>

(5x ^ 2 <em>- 8x</em> <u>+ 120</u>) + (- 3x ^ 2 <em>+ 10x</em> <u>- 13</u>) = 2x^2 <em>+ 2x</em> <u>+ 107</u>

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