
so notice above, the circle is centered at h,k or 0,0, the origin, and has a ratio of 5.
and y = 2, is just a horizontal line, check the picture below.
Answer:
26 1/2
Step-by-step explanation:
convert 4 5/12 into 53/12
multiply 53/12 by 6 to get 53/2
turn 53/2 into a mixed number = 26 1/2
Answer:
x = -3/2
Step-by-step explanation:
Let's solve your equation step-by-step.
4(x+2(3x−7))=22x−65
Step 1: Simplify both sides of the equation.
4(x+2(3x−7))=22x−65
(4)(x)+(4)(2(3x−7))=22x+−65(Distribute)
4x+24x+−56=22x+−65
(4x+24x)+(−56)=22x−65(Combine Like Terms)
28x+−56=22x−65
28x−56=22x−65
Step 2: Subtract 22x from both sides.
28x−56−22x=22x−65−22x
6x−56=−65
Step 3: Add 56 to both sides.
6x−56+56=−65+56
6x=−9
Step 4: Divide both sides by 6.
6x = -9
6 6
x = -3/2
Answer:
Subtract 58 from both sides
Step-by-step explanation:
93 = x + 58
Subtract 58 from both sides
93- 58 = x+58-58
35 = x