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Taya2010 [7]
3 years ago
7

Caiden earned $475 from mowing lawns last summer. He deposited this money in an account that pays an interest rate of 3.8% compo

unded annually. Caiden will not make any additional deposits or withdrawals. What will be his balance after 15 years? Round to the nearest hundredths place.
Mathematics
1 answer:
Korolek [52]3 years ago
5 0

Caiden's balance after 5 years would be $831

<u>Explanation:</u>

Given:

Principal, p = $475

Rate of interest = 3.8%

time, t = 15 years

Balance after 15 years = ?

We know:

Amount, A = P(1+\frac{r}{n})^n^t

where,

n = number of compounding periods

r = rate of interest

t = number of years

Substituting the value;

A = 475(1+\frac{3.8}{100} )^1^5\\\\A = 831

Therefore, Caiden's balance after 5 years would be $831

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What is 4 1/5+3 1/10<br><br> a. 7 2/15<br> b. 7 3/10<br> c. 7 1/5<br> d. 7 1/50
Black_prince [1.1K]
7 1/5th is the anwser but thats easy your just being lazy i think
7 0
3 years ago
identify the amplitude and period of the function then graph the function and describe the graph of G as a transformation of the
mrs_skeptik [129]

Given the function:

g(x)=cos4x

Let's find the amplitude and period of the function.

Apply the general cosine function:

f(x)=Acos(bx+c)+d

Where A is the amplitude.

Comparing both functions, we have:

A = 1

b = 4

Hence, we have:

Amplitude, A = 1

To find the period, we have:

\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}

Therefore, the period is = π/2

The graph of the function is shown below:

The parent function of the given function is:

f(x)=cosx

Let's describe the transformation..

Apply the transformation rules for function.

We have:

The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.

ANSWER:

Amplitude = 1

Period = π/2

Transformation = horizontal compression.

8 0
10 months ago
789/548x-89/887=688/8724 find x
Olin [163]

\frac{789}{548}x- \frac{89}{887}=\frac{688}{8724}

first we try to semplify as much as possible the fractions.

First we decompose the numbers

789 = 3 * 263

548 = 2 * 2 * 137 = 2^2

they have nothing in common, so the first fraction remains so

89 = 89 (prime number)

887 = 887 (prime number)

they have nothing in common, so the second one remains so

688 = 2 * 2 * 2 * 2 * 43 = 2^4 * 43

8724 = 2 * 2 * 3 * 727 = 2^2 * 3 * 727

they have 2^2 (=4) in common, so the numerator and the denominator can be devided by 4

\frac{688}{8724}= \frac{688:4}{8724:4}=\frac{172}{2181}

so:

\frac{789}{548}x- \frac{89}{887}=\frac{172}{2181}

now we calculate the common denominator

take the scomposition:

548 = 2^2 * 137

887 = 887

2181 = 3 * 727

take every number one time

so the common denominator is 2^2 * 137 * 887 * 727 * 3 = 1'060'131'756

now calculate every single numerator: first we divide each denominator by the common denominator, then we moltiply the result with each numerator

first fraction: 789/548

1060131756 / 548 = 1934547

1934547 * 789 = 1526357583

second fraction: 89/887

1060131756 / 887 = 1195188

1195188 * 89 = 106371732

third one: 172/2181

1060131756 / 2181 = 486076

486076 * 172 = 83605072

now we can delete the common denominator

1526357583x - 106371732 = 83605072

solve it

1526357583x = 83605072 + 106371732

1526357583x = 189976804

x = 1526357583 / 189976804

decompose

1526357583 = 887 * 3 * 3 * 727 * 263

189976804 = 137 * 2 * 2 * 211 * 53 * 31

nothing in common

x = 1526357583 / 189976804

8 0
2 years ago
What is the answer???
lisov135 [29]

Answer:

The answer is A.) 1

=) Hope this helps (=

5 0
3 years ago
Read 2 more answers
43. (09.01)
AlekseyPX

Answer:

That is;

{25,45,65}

Step-by-step explanation:

Here, we want to find the set of A n B

That is the set that contains values that are present in both sets A and B

Mathematically, that will be;

{25,45,65}

7 0
2 years ago
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