ans is b...multiply eqn 1 by -2 and eqn 2 by 3
=》 -6x + 10y = 4...eqn 3
=》 6x + 3y = 9...eqn 4
add eqn 3 and 4...
=》13y = 13
=》y =1 and x = 1
Answer:
D(4,-3)
Step-by-step explanation:
Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)
Let the coordinate of the fourth vertex be D(x,y).
We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.
The diagonals are BD and AC
Midpoint of BD = Midpoint of AC

The coordinates of the fourth vertex is D(4,-3)
To solve the inequality 3/10 is greater than or equal to k - 3/5, we must first set it up. Since 3/10 is greater than or equal to something, we will have a greater than or equal to symbol, with the 'mouth' pointing towards 3/10. Setting this up we get:
3/10 ≥ k - 3/5
Now we want to get k by itself on one side. We can do this by adding 3/5 to each side.
3/10 + 3/5 ≥ k
Simplify
9/10 ≥ k
Answer:
I would tell you
Step-by-step explanation:
you need to put 2 y and 2 x and that you need to divide
Answer:
no solution
Step-by-step explanation:
n -8 = 6+n
Subtract n from each side
n-n -8 = 6+n-n
-8 = 6
This is never true so there is no solution