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ki77a [65]
3 years ago
10

HD, JD, and KD are the perpendicular bisectors of triangle EFG. Find each length

Mathematics
1 answer:
erik [133]3 years ago
6 0
Since all three are perpendicular bisectors, the segment it bisects is equal on both sides.

Let's do segment EF.
HD bisects EF, therefore EF is split in half. All you have to do is add 16 to itself. This will be the same for the remaining two sides of that triangle. I'm hoping that was the only lengths you needed.
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100%

Step-by-step explanation:

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Solve this simultaneous e<br> x + y = 26<br> 3x + y = 56
trapecia [35]

Answer:

x= 15 and y= 11

Step-by-step explanation:

The goal here is to solve

x + y =26 and

3x + y =56 for the variables x and y.

First, let's work on your first equation, x + y =26

After this initial survey of the equations, the system of equations we'll set out to solve is:

x+y = 26 and 3x+y = 56

Let's start by solving x+y = 26 for the variable x.

Move the y to the right hand side by subtracting y from both sides, like this:

From the left hand side:

y - y = 0

The answer is x

From the right hand side:

The answer is 26-y

Now, the equation reads:

x = 26-y

To isolate the x, we have to divide both sides of the equation by the other variables

around the x on the left side of the equation.

and this is the final solution to your equation.

Next, let's solve 3x+y = 56 for the variable y.

Move the 3x to the right hand side by subtracting 3x from both sides, like this:

From the left hand side:

3x - 3x = 0

The answer is y

From the right hand side:

The answer is 56-3x

Now, the equation reads:

y = 56-3x

To isolate the y, we have to divide both sides of the equation by the other variables

around the y on the left side of the equation.

and this is the final solution to your equation.

Now, plug the earlier result, x=26-y, in for x everywhere it occurs in

y=56-3x.

This gives y=56-3(26-y). Now all we have to do is solve this for y,to have our first solution.

26-y evaluates to 26-y

Multiply 3 by 26-y

we multiply 3 by each term in 26-y term by term.

This is the distributive property of multiplication.

Multiply 3 and 26

1

3 × 26 = 78

Multiply 3 and -y

Multiply 1 and y

The y just gets copied along.

y

3 × -y = -3y

3*(26-y) evaluates to 78-3y

56 - 78 = -22

The answer is -22+3y

56-3*(26-y) evaluates to -22+3y

Move the 3y to the left hand side by subtracting 3y from both sides, like this:

From the left hand side:

y - 3y = -2y

The answer is -2y

From the right hand side:

3y - 3y = 0

The answer is -22

Now, the equation reads:

-2y = -22

To isolate the y, we have to divide both sides of the equation by the other variables

around the y on the left side of the equation.

The last step is to divide both sides of the equation by -2 like this:

To divide y by 1

The y just gets copied along in the numerator.

The answer is y

-2y ÷ -2 = y

-22 ÷ -2 = 11

The solution to your equation is:

y = 11

Lastly, to find the solution for x, we plug this answer for y into the earlier result that

x=26-y.

This gives x=26-(11). Now, simplify this.

26-(11) evaluates to 15

x= 15

So, the solutions to your equations are:

x= 15 and y= 11

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3 years ago
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For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to
Sloan [31]

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors A=i+j+kq and B=iq-2j+2kq are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. \vec{A}\cdot \vec{B}=0

Two vectors A=i+j+kq and B=iq-2j+2kq

(i+j+kq)\cdot (iq-2j+2kq)=0

(1)(q)+(1)(-2)+(q)(2q)=0

q-2+2q^2=0

2q^2+q-2=0

2q^2+q-2=0

Using quadratic formula,

q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}

q=\frac{-1\pm\sqrt{17}}{4}

q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}

q=0.781,-1.281

Therefore, The value of q are 0.781,-1.281.

6 0
3 years ago
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