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seropon [69]
3 years ago
10

Select each pair of functions that are inverses of each other. f (x) = left-brace (negative 5, negative 9), (negative 3, negativ

e 4), (0, 1), (3, 7), (6, 13) right-brace. G (x) = left-brace (negative 9, negative 5), (negative 4, negative 3), (1, 0), (7, 3), (13, 6), right-brace. f (x) = x + 7; g (x) = x minus 7 2 2-column tables with 4 rows. Table 1 is titled f (x). Column 1 is labeled x with entries 2, 3, 4, 5. Column 2 is labeled y with entries 3, 8, 15, 24. Table 2 is titled g (x). Column 1 is labeled x with entries 5, 4, 3, 2. Column 2 is labeled y with entries 24, 15, 8, 3.
Mathematics
2 answers:
Viktor [21]3 years ago
4 0

Answer:

The first two pairs of functions are inverse of each other

Step-by-step explanation:

Inverse functions?

1...................................

f(x) = {(-5, -9), (-3, -4), (0,1), (3,7), (6,13)}

g(x) = {(-9,-5), (-4, -3), (1,0), (7,3), (13,6)}

  • Yes, this pair is inverse as all points of the functions have inverse values

2...................................

f(x) = x + 7 is given

Inverse of f(x) is

  • x = f'(x) + 7 ⇒ f'(x) = x - 7

Since g(x) = x - 7 it is inverse with f(x)

  • Yes, this pair is inverse as described above

3...................................

Data of f(x) and g(x)

x = {2, 3, 4, 5}      f(x) = {3, 8, 15, 24}

x = {5, 4, 3, 2}      g(x) = {24, 15, 8, 3}

  • No, as both functions have same domain and range
  • example is f(2) = 3 and g(2) = 3 as per table

olga_2 [115]3 years ago
4 0

Answer:

its A and B

Step-by-step explanation:

edg2902020242kl9o

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Answer:

x = 3.5y

Step-by-step explanation:

Simplifying

3x + 8y + -5x + -1y = 0

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3x + -5x + 8y + -1y = 0

Combine like terms: 3x + -5x = -2x

-2x + 8y + -1y = 0

Combine like terms: 8y + -1y = 7y

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Solving

-2x + 7y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7y' to each side of the equation.

-2x + 7y + -7y = 0 + -7y

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3 0
3 years ago
Awnser 4. 5. and 6. please
vivado [14]
1 1/4 -3/8 equals 0.875 that's the answer for Number 4
8 0
3 years ago
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A chemist whishes to prepare 100 liters of 45% purity of sulphuric acid .He has two kinds of acid solutions in stock ,one is 55%
tester [92]

Answer:

the chemist should use 60 liters of 55% solution and 40  litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.

Step-by-step explanation:

From the given information,

Let x be the litres of 55% pure solution

Let y be the litres of 30% pure solution

Also;

Given that our total volume of solution is  100 litres

x+y =100  ---- (1)

The total solution of pure by related by the sum of the individual pure concentrations to make up the concentration of final solution.

(0.55)(x)+(0.30)(y) = 0.45(100) ---- (2)

From equation (1)

Let ; y = 100 - x

Replacing the value for y = 100 - x into equation (2)

(0.55)(x)+(0.30)(100-x) = 0.45(100)

0.55x + 30 - 0.30x = 45

0.55x - 0.30x = 45 - 30

0.25x = 15

x = 15/0.25

x = 60 liters of 55% solution

From ; y = 100 - x

y = 100 - 60

y = 40  litres of 30% solution.

Therefore, the chemist should use 60 liters of 55% solution and 40  litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.

7 0
4 years ago
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WINSTONCH [101]

Answer:

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Step-by-step explanation:

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