Answer: max = 10
iqr = 2
third quartille = 8
half the data values lie between 6 & 8
Step-by-step explanation:
You can "add" like you say or you could just call it subtracting. If you subtract 5 from 5 you still get zero. Then on the right side, you would do the same. You would subtract 5 from 12 getting x, which is 7.
If you added you would still get the same answers but it is easier to say just subtract. Anything you do to the left, do to the right.
Hope this helps :)
Answer:
Below in bold.
Step-by-step explanation:
The surface area of the box
= x^2 + 4hx where x = a side of the square base and h is the height.
So x^2 + 4hx = 8
The volume of the box
V = x^2h
From the first equation we solve for h
4hx = 8 - x^2
h = (8 - x^2) / 4x
Now we substitute for h in the formula for the volume:
V = x^2 * (8 - x^2) / 4x
V = 8x^2 - x^4 / 4x
V = 2x - 0.25x^3
Finding the derivative:
V' = 2 - 0.75x^2 = 0 for max/mimn values
x^2 = 2/ 0.75 = 2.667
x = 1.633.
So the length and width of the base is 1.633 m and the height
= ( 8 - 2.667) / (4*1.633)
= 0.816 m
The maximum volume = 0.816 * 2.667 = 2.177 m^2.
The answers are correct to the nearest thousandth.
Answer:
c
Step-by-step explanation:
Answer:
sorry, thought I could help. horrible at math.