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3 years ago

A celebrity has 50,000 followers on Instagram. The number of followers grows by 45% each year.

Mathematics

1 answer:

Fudgin [204]3 years ago

6 0

Answer:

230,000

Step-by-step explanation:

45% of 50,000 is 22,500

If the amount of followers raise by this much per year and you need to find how many they will have after 8 years, multiply 22,500 by 8

22,500 x 8 = 180,000

50,000 + 180,000 = 230,000

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Six more than twice a number is 24

Mars2501 [29]

Answer:

Step-by-step explanation:

I would say the answer is 6

6 + 6 than times by two is 24

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3 years ago

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Answer: DO I LOOK GOOD?

Step-by-step explanation:

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2 years ago

For how many minutes did Lynn run at a greater speed than Kael? 12 17 23 28.

Archy [21]

Answer:

28 minutes.

Step-by-step explanation:

We can see from our graph that 12 minutes after starting the race Lynn left Kael behind and he ran at a greater speed till the race ended after 40 minutes.

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2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

2x−4y=20 whats the answer

alexdok [17]

The answer is

x=10+2y

Steps:

2(x-2y)=20

x-2y=20/2 (in fraction form 20/2)

x-2y=10

X=10+2y

4 0

3 years ago

Read 2 more answers