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3 years ago

If there are 24 cats in the exhibit, how many tigers do you have?

Mathematics

2 answers:

Basile [38]3 years ago

8 0

Answer:

Step-by-step explanation:

If you have 8 loins and 4 tigers you add those up, you now have 12, if you have 24 cats that means that you double that, 12 x 2 =24 (boom) so now you know you just have to double 4 into 8.

Because for every 8 loins there are there are 4 tigers.

(double trouble)

galina1969 [7]3 years ago

5 0

There would be 8 tigers in the exhibit. Hope this helps.

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Charles has 9 times as many red marbles as blue marbles.

djyliett [7]

Answer:

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Step-by-step explanation:

Red = r, blue = b,

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r = b + 288

Substitute:

9b = b + 288
8b = 288
b = 288/8
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r = 288 + 26 = 314

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3 years ago

Which is equal to 8^-10/8^5 ?

makkiz [27]

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$\frac{ \frac{1}{ 8^{10} } }{ \frac{1}{ 8^{5} } }$

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3 years ago

The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.

malfutka [58]

The number of pencils sold on the first day is 5 pencils.

The number of notebooks sold on the first day is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day 35 notebooks.

Step-by-step explanation:

Given data,

The total number of notebooks in the store = 45 notebooks.
The total number of Pencils in the store = 15 pencils.
The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

In the first day :

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day = x

And, the number of notebooks sold on the first day = 2x (Twice as pencils).

In the second day :

The number of sale of notebooks and pencils are given by,

For every 7 notebooks sold, 2 pencils were sold.

The number of pencils sold on the second day = 2y

The number of notebooks sold on the second day = 7y

The equation is framed for number of notebooks sold on each day :

The number of notebooks sold ⇒ 2x + 7y = 45 -------(1)

The equation is framed for number of pencils sold on each day :

The number of pencils sold: x + 2y = 15 ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

2x + 7y = 45

- (2x + 4y) = 30

3y = 15

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day = x ⇒ 5 pencils

The number of notebooks sold on the first day = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day = 2y ⇒ 10 pencils

The number of notebooks sold on the second day = 7y ⇒ 35 notebooks.

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2 years ago